# h. Your argument diverts your attention from the police car for 2.0 s (long enough for you to look at the phone and yell,â€œI won’t do that!â€). At the beginning of that 2.0 s, the police officer beg

### Video Transcript

here for party. Let ‘s beginning note that the initial equals here we can save the initial is 110 kilometers per hour. Let ‘s barely convert very promptly 1000 meters per kilometer and for every one hour there are 3600 seconds. This is giving us 30 point 56 meters per second. now, at this luff, we know that here, Um if there is we have a meter interval of 2.0 seconds. We can say that the distance between the two cars was 25 meters. Um we can say delta x of us or you basically of the car would be 61 0.11 meters and then delta X for the police car Ah would be equal to 51 0.11 meters. We know that hera delta ten of both of the cars here would be 10 meters. so basically you have decreased the distance between the two cars by 10 meters, where the initial distance was already 25 meters. therefore here we can say the new distance between cars would be 25 minus 10 or we can merely say 15 meter, so this would be the modern distance between the cars. After a time time interval of 2.0 seconds for function B, we ‘re going to add 0.4 seconds to the considerations of interface A. so here Delta T is equaling 2.4 seconds. And during this time, we can say that you ‘re traveling 73.33 meters and the patrol car that is decelerating has traveled 58.93 meters. now here. Ah, the initial distance between cars uh D is equaling again. 25 meters. But immediately D knew, um is going to be 10.6 meters. so basically 73.33 minus 58.93 is 14.4 and then 25 meters minus 14.4 is, of course, giving us 10.6 meters. therefore 10.6 meters is the new distance between you and the collar car. now, at the start of your separate, let ‘s call this tea initial. so, uh, start of breaking for your cable car. We can say that here. The amphetamine of the police car is at T initial is going to be equal to 30.56 We can say Ah, we can simply say, um, speed of the patrol cable car. That thymine initial, this would be equal to 30 0.56 minus five times 2.4. Ah, this is equaling 18.56 meters per second. And we know that collision occurs at time t so we can say at a time. sol at T simply the exposition of the patrol car is equaling the place exposition of your car. thus basically we ‘re going to choose such that your put is ten equals zero and the exposition at T not if the adam of you at T not is equaling zero meters and then we can say adjacent of the police at T not is equaling 10.6 meters indeed basically again 10.6 meters, 10.6 meters because that would be our newly distance between the two cars. so now we ‘re going to apply equality to 15 and we can say that the exposition of the patrol cable car subtraction 10.6 would be equal to 18.56 times T minus T initial minus 1/2 times five times triiodothyronine minus t not squared. We can say the exhibition of yourself of your own car is 30 0.56 times T minus thyroxine initial. And then here it would be minus 1/2 times five times T minus deoxythymidine monophosphate initial square. immediately we ‘re going to subtract the two equations. Ah, By subtracting, we find that here 10.6, this would be equal to 30 0.56 subtraction 18.56 times T subtraction thyroxine initial and we simply solve, solve and say 0.883 seconds equals the deviation in time. then basically at that time, your accelerate is going to be 30 0.56 plus the acceleration times T minus thymine initial. And this would be equal to 30 0.56 minus five times 50.883 seconds. And this is approximately eat, equaling 26 meters per moment. So basically, you ‘re traveling 26 meters per second. When you hit the hook cable car. If you wanted to convert, this is approximately 90 or kilometers per hour. So you ‘re actually going quite fast when you hit the bull car. That is the end of the solution. Thank you for watching

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Category : Car Brakes